finding a week on basis of another week Practice Questions Answers Test with Solutions & More Shortcuts
calendar PRACTICE TEST [4 - EXERCISES]
basic calendar problems
find a day with reference day
find a day without reference day
finding a week on basis of another week
Question : 6 [S.S.C. (10 + 2) 2010]
If a day before yesterday was Thursday, then when will Sunday fall?
a) Today
b) 2nd day after today
c) Tomorrow
d) A day after tomorrow
Answer »Answer: (c)
A day before yesterday = Thursday
Yesterday = Thursday + 1 = Friday
Today = Friday + 1 = Saturday
Therefore, Sunday = Saturday + 1 = Tomorrow
Question : 7
Arvinth reaches a certain place on Friday and found he reaches the place 3 days before. If he had reached the place on coming Sunday, then how many days before or after he would have reached the place?
a) One day after
b) One day before
c) 2 days before
d) 2 days after
Answer »Answer: (b)
The correct day on which Anil has to reach the place = Friday + 3 = Monday.
Therefore, if Anil reaches on Sunday, then he reaches there on the day which is (Monday - 1) or 1 day before the correct day.
Question : 8 [S.S.C. (CPO) 2011]
Subha went to watch the movie 9 days ago. She goes to watch movies only on Thursday, what is the day of the week today?
a) Thursday
b) Saturday
c) Sunday
d) Monday
Answer »Answer: (b)
Day 9 days ago = Thursday
Therefore, Today = Thursday + 9
= Thursday + 7 + 2
= Thursday + 2 = Saturday
Question : 9
On 8th Feb 2005 it was Tuesday. What was the day of the week on 8th Feb 2004?
a) Tuesday
b) Monday
c) Sunday
d) Wednesday
Answer »Answer: (c)
Question : 10 [DMRC-(CRA), 2016]
What was the day of the week on 15 August 1947?
a) Saturday
b) Friday
c) Thursday
d) Wednesday
Answer »Answer: (b)
15 August 1947 means,
1946 complete years + first 7 months up to July 1947 + 15 days of August 1947
1600 years have 0 odd days.
300 years have 1 odd day
46 years have 11 leap years and
35 ordinary years = (11 × 2) + (35 × 1)
= 22 + 35 = 57 odd days
= 8 × 7 + 1 odd days = 8 weeks + 1 odd day
Up to 1946 there are 1 + 1 = 2 odd days
January 1947 = 3 odd days
February 1947 = 0 odd days (1947 is a normal year)
March 1947 = 3 odd days
April 1947 = 2 odd days
May 1947 = 3 odd days
June 1947 = 2 odd days
July 1947 = 3 odd days
Up to 15 August = 15 odd days
Total number od odd days up to 15 August 1947
= 2 + 3 + 0 + 3 + 2 + 3 + 2 + 3 + 15
= 33 odd days.
Hence, 15th August 1947 was Friday.
IMPORTANT verbal reasoning EXERCISES
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